128=(2n)^3/2

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Solution for 128=(2n)^3/2 equation: 


n in (-oo:+oo)

128 = ((2*n)^3)/2 // - ((2*n)^3)/2

128-(((2*n)^3)/2) = 0

-4*n^3 = -128 // : -4

n^3 = 32

n^3 = 32 // ^ 1/3

n = 2*4^(1/3)

n = 2*4^(1/3)

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